WebThe equation that relates these variables resembles the equation for the period of a pendulum. The equation is. T = 2•Π• (m/k).5. where T is the period, m is the mass of the object attached to the spring, and k is the spring constant of the spring. WebClick here👆to get an answer to your question ️ By suspending a mass of 0.50 kg, a spring is stretched by 8.20 m. If a mass of 0.25 kg is suspended, then its period of oscillation will be :(Take g = 10 ms^-2 )
SOLVED:Damping is negligible for a 0.150 -kg mass hanging ... - …
WebDamping is negligible for a 0.150-kg object hanging from a light, 6.30-N/m spring. A sinusoidal force with an amplitude of 1.70 N drives the system. At what frequency will the … WebDamping is negligible for a 0.150 k g object hanging from a light, 6.30 N / m spring. A sinusoidal force with an amplitude of 1.70 N drives the system. At what frequency will the force make the object vibrate with an amplitude of 0.440 m ? phm register my athlete
In a container of negligible mass , 0.150 kg of ice at 0^∘C
WebFind step-by-step Physics solutions and your answer to the following textbook question: Damping is negligible for a 0.150-kg object hanging from a light, 6.30-N/m spring. A … WebDamping is negligible for a 0.175-kg object hanging from a light, 6.30-N/m spring. A sinusoidal force with an amplitude of 1.70 N drives the system. At what frequency will the force make the object vi; Damping is negligible for a 0.145 kg object hanging from a light 6.30 N/m spring. A sinusoidal force with an amplitude of 1.70 N drives the system. WebDec 16, 2024 · The mass of the converted water to steam is 0.0186 ,,kg. Now to calculate the steam still there without converted to water it would be. 0.0400 − 0.0186 = 0.0214 k g. And for the water still in the container we would sum the mass of the water and the condensed steam to calculate the total mass of water. m w = 0.0186 + 0.2. phm reliable catering excel